25511131 has 4 divisors (see below), whose sum is σ = 25529112. Its totient is φ = 25493152.

The previous prime is 25511113. The next prime is 25511149. The reversal of 25511131 is 13111552.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (25511113) and next prime (25511149).

It is a cyclic number.

It is not a de Polignac number, because 25511131 - 2¹⁵ = 25478363 is a prime.

It is a super-2 number, since 2×25511131² = 1301635609798322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25511099 and 25511108.

It is not an unprimeable number, because it can be changed into a prime (25511231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6661 + ... + 9766.

It is an arithmetic number, because the mean of its divisors is an integer number (6382278).

Almost surely, 2^25511131 is an apocalyptic number.

25511131 is a deficient number, since it is larger than the sum of its proper divisors (17981).

25511131 is a wasteful number, since it uses less digits than its factorization.

25511131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17980.

The product of its digits is 150, while the sum is 19.

The square root of 25511131 is about 5050.8544821644. The cubic root of 25511131 is about 294.3810867938.

Adding to 25511131 its reverse (13111552), we get a palindrome (38622683).

The spelling of 25511131 in words is "twenty-five million, five hundred eleven thousand, one hundred thirty-one".