Base | Representation |
---|---|
bin | 100101000111111010110… |
… | …111010100101001110001 |
3 | 100000212220020122211112220 |
4 | 211013322313110221301 |
5 | 313244200322204131 |
6 | 5231545333511253 |
7 | 352212145502331 |
oct | 45077267245161 |
9 | 10025806584486 |
10 | 2551124413041 |
11 | 8a3a20250506 |
12 | 3525124a2529 |
13 | 15675439c809 |
14 | 8b6918990c1 |
15 | 4656205ee96 |
hex | 251fadd4a71 |
2551124413041 has 16 divisors (see below), whose sum is σ = 3410797828800. Its totient is φ = 1696101156288.
The previous prime is 2551124412989. The next prime is 2551124413051. The reversal of 2551124413041 is 1403144211552.
It is not a de Polignac number, because 2551124413041 - 211 = 2551124410993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2551124412993 and 2551124413011.
It is not an unprimeable number, because it can be changed into a prime (2551124413051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12539115 + ... + 12740943.
It is an arithmetic number, because the mean of its divisors is an integer number (213174864300).
Almost surely, 22551124413041 is an apocalyptic number.
It is an amenable number.
2551124413041 is a deficient number, since it is larger than the sum of its proper divisors (859673415759).
2551124413041 is a wasteful number, since it uses less digits than its factorization.
2551124413041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 213328.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 2551124413041 its reverse (1403144211552), we get a palindrome (3954268624593).
The spelling of 2551124413041 in words is "two trillion, five hundred fifty-one billion, one hundred twenty-four million, four hundred thirteen thousand, forty-one".
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