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255113131 = 7132803441
BaseRepresentation
bin11110011010010…
…11011110101011
3122210001002102111
433031023132223
51010302110011
641151543151
76215266030
oct1715133653
9583032374
10255113131
111210062a9
127152aab7
1340b12b20
1425c4b387
15175e4121
hexf34b7ab

255113131 has 8 divisors (see below), whose sum is σ = 313985504. Its totient is φ = 201847680.

The previous prime is 255113129. The next prime is 255113143. The reversal of 255113131 is 131311552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 255113131 - 21 = 255113129 is a prime.

It is a super-2 number, since 2×2551131312 = 130165419217246322, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (255113191) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1401630 + ... + 1401811.

It is an arithmetic number, because the mean of its divisors is an integer number (39248188).

Almost surely, 2255113131 is an apocalyptic number.

255113131 is a deficient number, since it is larger than the sum of its proper divisors (58872373).

255113131 is a wasteful number, since it uses less digits than its factorization.

255113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2803461.

The product of its digits is 450, while the sum is 22.

The square root of 255113131 is about 15972.2612988894. The cubic root of 255113131 is about 634.2263345192.

Adding to 255113131 its reverse (131311552), we get a palindrome (386424683).

The spelling of 255113131 in words is "two hundred fifty-five million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 7 13 91 2803441 19624087 36444733 255113131