Base | Representation |
---|---|
bin | 1110110110011000011… |
… | …1010110110100111011 |
3 | 220101111111021120000001 |
4 | 3231212013112310323 |
5 | 13134434231300003 |
6 | 313110535053431 |
7 | 24301006362262 |
oct | 3554607266473 |
9 | 811444246001 |
10 | 255116275003 |
11 | 992155393a7 |
12 | 41539b11277 |
13 | 1b09903c055 |
14 | c4c20dd5d9 |
15 | 698208c61d |
hex | 3b661d6d3b |
255116275003 has 4 divisors (see below), whose sum is σ = 255216362400. Its totient is φ = 255016187608.
The previous prime is 255116274947. The next prime is 255116275021. The reversal of 255116275003 is 300572611552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 255116275003 - 229 = 254579404091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (255116273003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50039875 + ... + 50044972.
It is an arithmetic number, because the mean of its divisors is an integer number (63804090600).
Almost surely, 2255116275003 is an apocalyptic number.
255116275003 is a deficient number, since it is larger than the sum of its proper divisors (100087397).
255116275003 is a wasteful number, since it uses less digits than its factorization.
255116275003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100087396.
The product of its (nonzero) digits is 63000, while the sum is 37.
Adding to 255116275003 its reverse (300572611552), we get a palindrome (555688886555).
The spelling of 255116275003 in words is "two hundred fifty-five billion, one hundred sixteen million, two hundred seventy-five thousand, three".
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