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2551240005401 = 11032323125187
BaseRepresentation
bin100101001000000001110…
…000010001011100011001
3100000220012022011112110102
4211020001300101130121
5313244414420133101
65232005023225145
7352215051145313
oct45100160213431
910026168145412
102551240005401
118a3a7a52178a
123525451481b5
13156772312469
148b6a2d887b3
154656c29486b
hex25201c11719

2551240005401 has 4 divisors (see below), whose sum is σ = 2551263240912. Its totient is φ = 2551216769892.

The previous prime is 2551240005397. The next prime is 2551240005407. The reversal of 2551240005401 is 1045000421552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2551240005401 - 22 = 2551240005397 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2551240005407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11452271 + ... + 11672916.

It is an arithmetic number, because the mean of its divisors is an integer number (637815810228).

Almost surely, 22551240005401 is an apocalyptic number.

It is an amenable number.

2551240005401 is a deficient number, since it is larger than the sum of its proper divisors (23235511).

2551240005401 is a wasteful number, since it uses less digits than its factorization.

2551240005401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23235510.

The product of its (nonzero) digits is 8000, while the sum is 29.

Adding to 2551240005401 its reverse (1045000421552), we get a palindrome (3596240426953).

The spelling of 2551240005401 in words is "two trillion, five hundred fifty-one billion, two hundred forty million, five thousand, four hundred one".

Divisors: 1 110323 23125187 2551240005401