Search a number
-
+
2551255235 = 5510251047
BaseRepresentation
bin1001100000010001…
…0001000011000011
320120210122012020122
42120010101003003
520211110131420
61101054130455
7120136211624
oct23004210303
96523565218
102551255235
11109a131901
125b24b0a2b
13318736ca9
141a2b93a4b
15edea2725
hex981110c3

2551255235 has 4 divisors (see below), whose sum is σ = 3061506288. Its totient is φ = 2041004184.

The previous prime is 2551255219. The next prime is 2551255241. The reversal of 2551255235 is 5325521552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2551255235 - 24 = 2551255219 is a prime.

It is a super-2 number, since 2×25512552352 = 13017806548229810450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2551255195 and 2551255204.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255125519 + ... + 255125528.

It is an arithmetic number, because the mean of its divisors is an integer number (765376572).

Almost surely, 22551255235 is an apocalyptic number.

2551255235 is a deficient number, since it is larger than the sum of its proper divisors (510251053).

2551255235 is an equidigital number, since it uses as much as digits as its factorization.

2551255235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 510251052.

The product of its digits is 75000, while the sum is 35.

The square root of 2551255235 is about 50509.9518411966. The cubic root of 2551255235 is about 1366.4213410203.

Adding to 2551255235 its reverse (5325521552), we get a palindrome (7876776787).

The spelling of 2551255235 in words is "two billion, five hundred fifty-one million, two hundred fifty-five thousand, two hundred thirty-five".

Divisors: 1 5 510251047 2551255235