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255130104145 = 5717428790091
BaseRepresentation
bin1110110110011011110…
…0000111000101010001
3220101112110022011000111
43231212330013011101
513140001301313040
6313112151321321
724301235050420
oct3554674070521
9811473264014
10255130104145
1199222324444
1241542680241
131b09bb71787
14c4c3c9d2b7
1569833bedea
hex3b66f07151

255130104145 has 16 divisors (see below), whose sum is σ = 370474639488. Its totient is φ = 164655394560.

The previous prime is 255130104139. The next prime is 255130104149. The reversal of 255130104145 is 541401031552.

It is not a de Polignac number, because 255130104145 - 23 = 255130104137 is a prime.

It is a super-3 number, since 3×2551301041453 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (255130104149) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 214394451 + ... + 214395640.

It is an arithmetic number, because the mean of its divisors is an integer number (23154664968).

Almost surely, 2255130104145 is an apocalyptic number.

It is an amenable number.

255130104145 is a deficient number, since it is larger than the sum of its proper divisors (115344535343).

255130104145 is a wasteful number, since it uses less digits than its factorization.

255130104145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 428790120.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 255130104145 its reverse (541401031552), we get a palindrome (796531135697).

The spelling of 255130104145 in words is "two hundred fifty-five billion, one hundred thirty million, one hundred four thousand, one hundred forty-five".

Divisors: 1 5 7 17 35 85 119 595 428790091 2143950455 3001530637 7289431547 15007653185 36447157735 51026020829 255130104145