255132313413241 has 4 divisors (see below), whose sum is σ = 278326160087184. Its totient is φ = 231938466739300.

The previous prime is 255132313413149. The next prime is 255132313413283. The reversal of 255132313413241 is 142314313231552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 255132313413241 - 2¹⁷ = 255132313282169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255132313413194 and 255132313413203.

It is not an unprimeable number, because it can be changed into a prime (255132313413841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11596923336955 + ... + 11596923336976.

It is an arithmetic number, because the mean of its divisors is an integer number (69581540021796).

Almost surely, 2^{255132313413241} is an apocalyptic number.

It is an amenable number.

255132313413241 is a deficient number, since it is larger than the sum of its proper divisors (23193846673943).

255132313413241 is a wasteful number, since it uses less digits than its factorization.

255132313413241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23193846673942.

The product of its digits is 259200, while the sum is 40.

Adding to 255132313413241 its reverse (142314313231552), we get a palindrome (397446626644793).

The spelling of 255132313413241 in words is "two hundred fifty-five trillion, one hundred thirty-two billion, three hundred thirteen million, four hundred thirteen thousand, two hundred forty-one".