Base | Representation |
---|---|
bin | 1110110110011100100… |
… | …1001001011000000011 |
3 | 220101112200201202121220 |
4 | 3231213021021120003 |
5 | 13140003140141121 |
6 | 313112352450123 |
7 | 24301306102326 |
oct | 3554711113003 |
9 | 811480652556 |
10 | 255133521411 |
11 | 9922424892a |
12 | 41543849943 |
13 | 1b09c79a022 |
14 | c4c450c7bd |
15 | 69838476c6 |
hex | 3b67249603 |
255133521411 has 4 divisors (see below), whose sum is σ = 340178028552. Its totient is φ = 170089014272.
The previous prime is 255133521367. The next prime is 255133521421. The reversal of 255133521411 is 114125331552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 255133521411 - 27 = 255133521283 is a prime.
It is a super-2 number, since 2×2551335214112 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (255133521421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42522253566 + ... + 42522253571.
It is an arithmetic number, because the mean of its divisors is an integer number (85044507138).
Almost surely, 2255133521411 is an apocalyptic number.
255133521411 is a deficient number, since it is larger than the sum of its proper divisors (85044507141).
255133521411 is an equidigital number, since it uses as much as digits as its factorization.
255133521411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85044507140.
The product of its digits is 18000, while the sum is 33.
Adding to 255133521411 its reverse (114125331552), we get a palindrome (369258852963).
The spelling of 255133521411 in words is "two hundred fifty-five billion, one hundred thirty-three million, five hundred twenty-one thousand, four hundred eleven".
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