Base | Representation |
---|---|
bin | 111010000000110010101101… |
… | …101000001000110111001011 |
3 | 1020110101020220102222011120020 |
4 | 322000302231220020313023 |
5 | 231420213033424411021 |
6 | 2302350120514431523 |
7 | 104512224360005361 |
oct | 7200625550106713 |
9 | 1213336812864506 |
10 | 255141150232011 |
11 | 743288328763aa |
12 | 24748092b925a3 |
13 | ac49926a25954 |
14 | 4700c7cc99631 |
15 | 1e76c180eb7c6 |
hex | e80cada08dcb |
255141150232011 has 4 divisors (see below), whose sum is σ = 340188200309352. Its totient is φ = 170094100154672.
The previous prime is 255141150231953. The next prime is 255141150232019. The reversal of 255141150232011 is 110232051141552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 255141150232011 - 229 = 255140613361099 is a prime.
It is not an unprimeable number, because it can be changed into a prime (255141150232019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42523525038666 + ... + 42523525038671.
It is an arithmetic number, because the mean of its divisors is an integer number (85047050077338).
Almost surely, 2255141150232011 is an apocalyptic number.
255141150232011 is a deficient number, since it is larger than the sum of its proper divisors (85047050077341).
255141150232011 is an equidigital number, since it uses as much as digits as its factorization.
255141150232011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85047050077340.
The product of its (nonzero) digits is 12000, while the sum is 33.
The spelling of 255141150232011 in words is "two hundred fifty-five trillion, one hundred forty-one billion, one hundred fifty million, two hundred thirty-two thousand, eleven".
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