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255147113 = 1319626701
BaseRepresentation
bin11110011010100…
…11110001101001
3122210002211001002
433031103301221
51010304201423
641152404345
76215500064
oct1715236151
9583084032
10255147113
11121029891
12715466b5
1340b25430
1425c598db
15175ee228
hexf353c69

255147113 has 4 divisors (see below), whose sum is σ = 274773828. Its totient is φ = 235520400.

The previous prime is 255147089. The next prime is 255147131. The reversal of 255147113 is 311741552.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18079504 + 237067609 = 4252^2 + 15397^2 .

It is a cyclic number.

It is not a de Polignac number, because 255147113 - 26 = 255147049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (255147163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9813338 + ... + 9813363.

It is an arithmetic number, because the mean of its divisors is an integer number (68693457).

Almost surely, 2255147113 is an apocalyptic number.

It is an amenable number.

255147113 is a deficient number, since it is larger than the sum of its proper divisors (19626715).

255147113 is a wasteful number, since it uses less digits than its factorization.

255147113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19626714.

The product of its digits is 4200, while the sum is 29.

The square root of 255147113 is about 15973.3250452121. The cubic root of 255147113 is about 634.2544936897.

Adding to 255147113 its reverse (311741552), we get a palindrome (566888665).

The spelling of 255147113 in words is "two hundred fifty-five million, one hundred forty-seven thousand, one hundred thirteen".

Divisors: 1 13 19626701 255147113