Base | Representation |
---|---|
bin | 100101001000111000001… |
… | …011000101010110101001 |
3 | 100000222112221010122022100 |
4 | 211020320023011112221 |
5 | 313303302132102213 |
6 | 5232235400044013 |
7 | 352246505411205 |
oct | 45107013052651 |
9 | 10028487118270 |
10 | 2552153003433 |
11 | 8a43a8921710 |
12 | 35275aa63609 |
13 | 15688950a197 |
14 | 8b74c329b05 |
15 | 465c24dc773 |
hex | 252382c55a9 |
2552153003433 has 12 divisors (see below), whose sum is σ = 4021574429808. Its totient is φ = 1546759395960.
The previous prime is 2552153003401. The next prime is 2552153003443. The reversal of 2552153003433 is 3343003512552.
2552153003433 is a `hidden beast` number, since 2 + 5 + 5 + 2 + 1 + 5 + 300 + 343 + 3 = 666.
It is not a de Polignac number, because 2552153003433 - 25 = 2552153003401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2552153003443) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12889661535 + ... + 12889661732.
It is an arithmetic number, because the mean of its divisors is an integer number (335131202484).
Almost surely, 22552153003433 is an apocalyptic number.
It is an amenable number.
2552153003433 is a deficient number, since it is larger than the sum of its proper divisors (1469421426375).
2552153003433 is a wasteful number, since it uses less digits than its factorization.
2552153003433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25779323284 (or 25779323281 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 36.
Adding to 2552153003433 its reverse (3343003512552), we get a palindrome (5895156515985).
The spelling of 2552153003433 in words is "two trillion, five hundred fifty-two billion, one hundred fifty-three million, three thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •