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2552552505553 = 13711186168223
BaseRepresentation
bin100101001001001111111…
…111000100000011010001
3100001000120202212110012011
4211021033333010003101
5313310111420134203
65232343150502521
7352262426210341
oct45111777040321
910030522773164
102552552505553
118a4593387556
12352850804a41
13156921205c7b
148b789400d21
15465e760376d
hex2524ffc40d1

2552552505553 has 4 divisors (see below), whose sum is σ = 2552738687488. Its totient is φ = 2552366323620.

The previous prime is 2552552505533. The next prime is 2552552505599. The reversal of 2552552505553 is 3555052552552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2552552505553 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2552552505497 and 2552552505506.

It is not an unprimeable number, because it can be changed into a prime (2552552505533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93070401 + ... + 93097822.

It is an arithmetic number, because the mean of its divisors is an integer number (638184671872).

Almost surely, 22552552505553 is an apocalyptic number.

It is an amenable number.

2552552505553 is a deficient number, since it is larger than the sum of its proper divisors (186181935).

2552552505553 is a wasteful number, since it uses less digits than its factorization.

2552552505553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 186181934.

The product of its (nonzero) digits is 9375000, while the sum is 49.

The spelling of 2552552505553 in words is "two trillion, five hundred fifty-two billion, five hundred fifty-two million, five hundred five thousand, five hundred fifty-three".

Divisors: 1 13711 186168223 2552552505553