Base | Representation |
---|---|
bin | 1011100111000001011011… |
… | …11001000000001110001001 |
3 | 10100101122112110120020000120 |
4 | 11303200231321000032021 |
5 | 11321241023203302012 |
6 | 130144202352053453 |
7 | 5243325401301453 |
oct | 563405571001611 |
9 | 110348473506016 |
10 | 25530055525257 |
11 | 815326585aa68 |
12 | 2a43a8bb34289 |
13 | 113262122c12a |
14 | 6439387a72d3 |
15 | 2e4166b3158c |
hex | 17382de40389 |
25530055525257 has 4 divisors (see below), whose sum is σ = 34040074033680. Its totient is φ = 17020037016836.
The previous prime is 25530055525253. The next prime is 25530055525277. The reversal of 25530055525257 is 75252555003552.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25530055525257 - 22 = 25530055525253 is a prime.
It is not an unprimeable number, because it can be changed into a prime (25530055525253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4255009254207 + ... + 4255009254212.
It is an arithmetic number, because the mean of its divisors is an integer number (8510018508420).
Almost surely, 225530055525257 is an apocalyptic number.
It is an amenable number.
25530055525257 is a deficient number, since it is larger than the sum of its proper divisors (8510018508423).
25530055525257 is an equidigital number, since it uses as much as digits as its factorization.
25530055525257 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8510018508422.
The product of its (nonzero) digits is 13125000, while the sum is 51.
The spelling of 25530055525257 in words is "twenty-five trillion, five hundred thirty billion, fifty-five million, five hundred twenty-five thousand, two hundred fifty-seven".
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