255301113 has 4 divisors (see below), whose sum is σ = 340401488. Its totient is φ = 170200740.

The previous prime is 255301103. The next prime is 255301139. The reversal of 255301113 is 311103552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 255301113 - 2⁴ = 255301097 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 255301113.

It is not an unprimeable number, because it can be changed into a prime (255301103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42550183 + ... + 42550188.

It is an arithmetic number, because the mean of its divisors is an integer number (85100372).

Almost surely, 2^255301113 is an apocalyptic number.

It is an amenable number.

255301113 is a deficient number, since it is larger than the sum of its proper divisors (85100375).

255301113 is an equidigital number, since it uses as much as digits as its factorization.

255301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85100374.

The product of its (nonzero) digits is 450, while the sum is 21.

The square root of 255301113 is about 15978.1448547696. The cubic root of 255301113 is about 634.3820743967.

Adding to 255301113 its reverse (311103552), we get a palindrome (566404665).

The spelling of 255301113 in words is "two hundred fifty-five million, three hundred one thousand, one hundred thirteen".