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255340011 = 385113337
BaseRepresentation
bin11110011100000…
…10110111101011
3122210110121122110
433032002313223
51010331340021
641200453403
76220232343
oct1716026753
9583417573
10255340011
11121150803
127161a263
1340b92184
1425ca9d23
151763b476
hexf382deb

255340011 has 4 divisors (see below), whose sum is σ = 340453352. Its totient is φ = 170226672.

The previous prime is 255340003. The next prime is 255340093. The reversal of 255340011 is 110043552.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 255340011 - 23 = 255340003 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 255340011.

It is not an unprimeable number, because it can be changed into a prime (255340511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42556666 + ... + 42556671.

It is an arithmetic number, because the mean of its divisors is an integer number (85113338).

Almost surely, 2255340011 is an apocalyptic number.

255340011 is a deficient number, since it is larger than the sum of its proper divisors (85113341).

255340011 is an equidigital number, since it uses as much as digits as its factorization.

255340011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85113340.

The product of its (nonzero) digits is 600, while the sum is 21.

The square root of 255340011 is about 15979.3620335732. The cubic root of 255340011 is about 634.4142911786.

Adding to 255340011 its reverse (110043552), we get a palindrome (365383563).

The spelling of 255340011 in words is "two hundred fifty-five million, three hundred forty thousand, eleven".

Divisors: 1 3 85113337 255340011