Base | Representation |
---|---|
bin | 100101001010000100010… |
… | …010110111010000010011 |
3 | 100001002211221020102212220 |
4 | 211022010102313100103 |
5 | 313313411102030001 |
6 | 5233010220552123 |
7 | 352323243555465 |
oct | 45120422672023 |
9 | 10032757212786 |
10 | 2553430111251 |
11 | 8a49a3803718 |
12 | 352a566b2643 |
13 | 156a30c8b496 |
14 | 8b82dbac135 |
15 | 466496a9c36 |
hex | 252844b7413 |
2553430111251 has 4 divisors (see below), whose sum is σ = 3404573481672. Its totient is φ = 1702286740832.
The previous prime is 2553430111217. The next prime is 2553430111303. The reversal of 2553430111251 is 1521110343552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2553430111251 - 214 = 2553430094867 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2553430111151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425571685206 + ... + 425571685211.
It is an arithmetic number, because the mean of its divisors is an integer number (851143370418).
Almost surely, 22553430111251 is an apocalyptic number.
2553430111251 is a deficient number, since it is larger than the sum of its proper divisors (851143370421).
2553430111251 is an equidigital number, since it uses as much as digits as its factorization.
2553430111251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 851143370420.
The product of its (nonzero) digits is 18000, while the sum is 33.
The spelling of 2553430111251 in words is "two trillion, five hundred fifty-three billion, four hundred thirty million, one hundred eleven thousand, two hundred fifty-one".
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