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255361768113 = 385120589371
BaseRepresentation
bin1110110111010010111…
…1110101101010110001
3220102010121012220020110
43231310233311222301
513140440103034423
6313151144531533
724310050133524
oct3556457655261
9812117186213
10255361768113
1199331073a71
12415a8180ba9
131b107b6424a
14c506964bbb
1569988d1193
hex3b74bf5ab1

255361768113 has 4 divisors (see below), whose sum is σ = 340482357488. Its totient is φ = 170241178740.

The previous prime is 255361768097. The next prime is 255361768127. The reversal of 255361768113 is 311867163552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 255361768113 - 24 = 255361768097 is a prime.

It is a super-2 number, since 2×2553617681132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (255361768213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42560294683 + ... + 42560294688.

It is an arithmetic number, because the mean of its divisors is an integer number (85120589372).

Almost surely, 2255361768113 is an apocalyptic number.

It is an amenable number.

255361768113 is a deficient number, since it is larger than the sum of its proper divisors (85120589375).

255361768113 is an equidigital number, since it uses as much as digits as its factorization.

255361768113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85120589374.

The product of its digits is 907200, while the sum is 48.

The spelling of 255361768113 in words is "two hundred fifty-five billion, three hundred sixty-one million, seven hundred sixty-eight thousand, one hundred thirteen".

Divisors: 1 3 85120589371 255361768113