Base | Representation |
---|---|
bin | 1011100111010001011111… |
… | …11110010101001110101011 |
3 | 10100102110210112210211002011 |
4 | 11303220233332111032223 |
5 | 11321411204141123201 |
6 | 130152150253220351 |
7 | 5244052210516213 |
oct | 563505776251653 |
9 | 110373715724064 |
10 | 25538680411051 |
11 | 8156991333355 |
12 | 2a456984916b7 |
13 | 1133397072052 |
14 | 644116055243 |
15 | 2e44bde13151 |
hex | 173a2ff953ab |
25538680411051 has 8 divisors (see below), whose sum is σ = 26168254816880. Its totient is φ = 24910726532832.
The previous prime is 25538680411007. The next prime is 25538680411063. The reversal of 25538680411051 is 15011408683552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 25538680411051 - 215 = 25538680378283 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25538680410986 and 25538680411004.
It is not an unprimeable number, because it can be changed into a prime (25538680411351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 405099996 + ... + 405163033.
It is an arithmetic number, because the mean of its divisors is an integer number (3271031852110).
Almost surely, 225538680411051 is an apocalyptic number.
25538680411051 is a deficient number, since it is larger than the sum of its proper divisors (629574405829).
25538680411051 is an equidigital number, since it uses as much as digits as its factorization.
25538680411051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 810263805.
The product of its (nonzero) digits is 1152000, while the sum is 49.
The spelling of 25538680411051 in words is "twenty-five trillion, five hundred thirty-eight billion, six hundred eighty million, four hundred eleven thousand, fifty-one".
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