255405343310451 has 12 divisors (see below), whose sum is σ = 372571490903040. Its totient is φ = 168584385022800.

The previous prime is 255405343310371. The next prime is 255405343310477. The reversal of 255405343310451 is 154013343504552.

255405343310451 is a `hidden beast` number, since 2 + 5 + 5 + 4 + 0 + 534 + 3 + 3 + 104 + 5 + 1 = 666.

It is not a de Polignac number, because 255405343310451 - 2¹¹ = 255405343308403 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255405343310397 and 255405343310406.

It is not an unprimeable number, because it can be changed into a prime (255405343310651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 140486986611 + ... + 140486988428.

It is an arithmetic number, because the mean of its divisors is an integer number (31047624241920).

Almost surely, 2^{255405343310451} is an apocalyptic number.

255405343310451 is a deficient number, since it is larger than the sum of its proper divisors (117166147592589).

255405343310451 is a wasteful number, since it uses less digits than its factorization.

255405343310451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 280973975146 (or 280973975143 counting only the distinct ones).

The product of its (nonzero) digits is 2160000, while the sum is 45.

The spelling of 255405343310451 in words is "two hundred fifty-five trillion, four hundred five billion, three hundred forty-three million, three hundred ten thousand, four hundred fifty-one".