Base | Representation |
---|---|
bin | 111010000101001010000101… |
… | …110100010110001100101011 |
3 | 1020111102221012112221001220000 |
4 | 322011022011310112030223 |
5 | 231440121413243220233 |
6 | 2303140011331234043 |
7 | 104543004221302224 |
oct | 7205120564261453 |
9 | 1214387175831800 |
10 | 255441130054443 |
11 | 74433a7a640a23 |
12 | 24796251748923 |
13 | ac6bcc260b368 |
14 | 47115b946824b |
15 | 1e7e923b21d13 |
hex | e85285d1632b |
255441130054443 has 40 divisors (see below), whose sum is σ = 386973137041920. Its totient is φ = 167889589161840.
The previous prime is 255441130054441. The next prime is 255441130054469. The reversal of 255441130054443 is 344450031144552.
255441130054443 is a `hidden beast` number, since 2 + 5 + 5 + 44 + 113 + 0 + 0 + 54 + 443 = 666.
It is not a de Polignac number, because 255441130054443 - 21 = 255441130054441 is a prime.
It is not an unprimeable number, because it can be changed into a prime (255441130054441) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 163395838 + ... + 164951756.
It is an arithmetic number, because the mean of its divisors is an integer number (9674328426048).
Almost surely, 2255441130054443 is an apocalyptic number.
255441130054443 is a deficient number, since it is larger than the sum of its proper divisors (131532006987477).
255441130054443 is a wasteful number, since it uses less digits than its factorization.
255441130054443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1584549 (or 1584540 counting only the distinct ones).
The product of its (nonzero) digits is 2304000, while the sum is 45.
Adding to 255441130054443 its reverse (344450031144552), we get a palindrome (599891161198995).
The spelling of 255441130054443 in words is "two hundred fifty-five trillion, four hundred forty-one billion, one hundred thirty million, fifty-four thousand, four hundred forty-three".
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