Base | Representation |
---|---|
bin | 1110110111101101010… |
… | …0110011000011101001 |
3 | 220102102021212100121220 |
4 | 3231323110303003221 |
5 | 13141201330320131 |
6 | 313210130052253 |
7 | 24312560122335 |
oct | 3557324630351 |
9 | 812367770556 |
10 | 255472120041 |
11 | 99388396006 |
12 | 4161911a089 |
13 | 1b124990848 |
14 | c51748c7c5 |
15 | 69a342ce96 |
hex | 3b7b5330e9 |
255472120041 has 16 divisors (see below), whose sum is σ = 349958578944. Its totient is φ = 165653437824.
The previous prime is 255472120027. The next prime is 255472120087. The reversal of 255472120041 is 140021274552.
It is not a de Polignac number, because 255472120041 - 25 = 255472120009 is a prime.
It is a super-3 number, since 3×2554721200413 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 255472119984 and 255472120011.
It is not an unprimeable number, because it can be changed into a prime (255472320041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85665 + ... + 719918.
It is an arithmetic number, because the mean of its divisors is an integer number (21872411184).
Almost surely, 2255472120041 is an apocalyptic number.
It is an amenable number.
255472120041 is a deficient number, since it is larger than the sum of its proper divisors (94486458903).
255472120041 is a wasteful number, since it uses less digits than its factorization.
255472120041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 808480.
The product of its (nonzero) digits is 22400, while the sum is 33.
Adding to 255472120041 its reverse (140021274552), we get a palindrome (395493394593).
The spelling of 255472120041 in words is "two hundred fifty-five billion, four hundred seventy-two million, one hundred twenty thousand, forty-one".
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