Base | Representation |
---|---|
bin | 10111110011000001… |
… | …101011111100110011 |
3 | 2102221202212022102111 |
4 | 113303001223330303 |
5 | 404312322022011 |
6 | 15423303030151 |
7 | 1563130424125 |
oct | 276301537463 |
9 | 72852768374 |
10 | 25552142131 |
11 | a92257763a |
12 | 4b5143b357 |
13 | 2542a46a39 |
14 | 1345833215 |
15 | 9e83da121 |
hex | 5f306bf33 |
25552142131 has 4 divisors (see below), whose sum is σ = 25666725952. Its totient is φ = 25437558312.
The previous prime is 25552142129. The next prime is 25552142141. The reversal of 25552142131 is 13124125552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 25552142131 - 21 = 25552142129 is a prime.
It is a super-2 number, since 2×255521421312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 25552142093 and 25552142102.
It is not an unprimeable number, because it can be changed into a prime (25552142141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57291576 + ... + 57292021.
It is an arithmetic number, because the mean of its divisors is an integer number (6416681488).
Almost surely, 225552142131 is an apocalyptic number.
25552142131 is a deficient number, since it is larger than the sum of its proper divisors (114583821).
25552142131 is a wasteful number, since it uses less digits than its factorization.
25552142131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 114583820.
The product of its digits is 12000, while the sum is 31.
Adding to 25552142131 its reverse (13124125552), we get a palindrome (38676267683).
The spelling of 25552142131 in words is "twenty-five billion, five hundred fifty-two million, one hundred forty-two thousand, one hundred thirty-one".
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