Base | Representation |
---|---|
bin | 1011101000000010100100… |
… | …01111010111100001111001 |
3 | 10100111222210112222222122020 |
4 | 11310001102033113201321 |
5 | 11322324132411343131 |
6 | 130212224351345053 |
7 | 5246004103652151 |
oct | 564012217274171 |
9 | 110458715888566 |
10 | 25565025106041 |
11 | 8167080214653 |
12 | 2a4a80b222189 |
13 | 1135a05062075 |
14 | 6454d4c35761 |
15 | 2e5011ba3996 |
hex | 1740523d7879 |
25565025106041 has 4 divisors (see below), whose sum is σ = 34086700141392. Its totient is φ = 17043350070692.
The previous prime is 25565025106039. The next prime is 25565025106079. The reversal of 25565025106041 is 14060152056552.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25565025106041 - 21 = 25565025106039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25565025105984 and 25565025106002.
It is not an unprimeable number, because it can be changed into a prime (25565025106141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4260837517671 + ... + 4260837517676.
It is an arithmetic number, because the mean of its divisors is an integer number (8521675035348).
Almost surely, 225565025106041 is an apocalyptic number.
It is an amenable number.
25565025106041 is a deficient number, since it is larger than the sum of its proper divisors (8521675035351).
25565025106041 is an equidigital number, since it uses as much as digits as its factorization.
25565025106041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8521675035350.
The product of its (nonzero) digits is 360000, while the sum is 42.
The spelling of 25565025106041 in words is "twenty-five trillion, five hundred sixty-five billion, twenty-five million, one hundred six thousand, forty-one".
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