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2557389441115 = 54969102933767
BaseRepresentation
bin100101001101110000010…
…010100000100001011011
3100001111001212102020101201
4211031300102200201123
5313400013144103430
65234503135055031
7352523331403315
oct45156022404133
910044055366351
102557389441115
118a6645739863
12353780671477
13157212340312
148bac79767b5
15467cc0998ca
hex253704a085b

2557389441115 has 8 divisors (see below), whose sum is σ = 3069484961760. Its totient is φ = 2045499797952.

The previous prime is 2557389441097. The next prime is 2557389441137. The reversal of 2557389441115 is 5111449837552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2557389441115 - 25 = 2557389441083 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51442039 + ... + 51491728.

It is an arithmetic number, because the mean of its divisors is an integer number (383685620220).

Almost surely, 22557389441115 is an apocalyptic number.

2557389441115 is a deficient number, since it is larger than the sum of its proper divisors (512095520645).

2557389441115 is a wasteful number, since it uses less digits than its factorization.

2557389441115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102938741.

The product of its digits is 6048000, while the sum is 55.

The spelling of 2557389441115 in words is "two trillion, five hundred fifty-seven billion, three hundred eighty-nine million, four hundred forty-one thousand, one hundred fifteen".

Divisors: 1 5 4969 24845 102933767 514668835 511477888223 2557389441115