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256000000001 = 349841731761
BaseRepresentation
bin1110111001101011001…
…0100000000000000001
3220110210002011102210112
43232122302200000001
513143242000000001
6313334344241105
724331630045064
oct3563262400001
9813702142715
10256000000001
1199629365039
1241745a70195
131b1aa157955
14c5676208db
1569d4951cbb
hex3b9aca0001

256000000001 has 4 divisors (see below), whose sum is σ = 256001081604. Its totient is φ = 255998918400.

The previous prime is 255999999989. The next prime is 256000000007. The reversal of 256000000001 is 100000000652.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 43664281600 + 212335718401 = 208960^2 + 460799^2 .

It is a cyclic number.

It is not a de Polignac number, because 256000000001 - 210 = 255999998977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (256000000007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16040 + ... + 715721.

It is an arithmetic number, because the mean of its divisors is an integer number (64000270401).

Almost surely, 2256000000001 is an apocalyptic number.

It is an amenable number.

256000000001 is a deficient number, since it is larger than the sum of its proper divisors (1081603).

256000000001 is an equidigital number, since it uses as much as digits as its factorization.

256000000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1081602.

The product of its (nonzero) digits is 60, while the sum is 14.

Adding to 256000000001 its reverse (100000000652), we get a palindrome (356000000653).

The spelling of 256000000001 in words is "two hundred fifty-six billion, one", and thus it is an aban number.

Divisors: 1 349841 731761 256000000001