Base | Representation |
---|---|
bin | 1110111001101100101… |
… | …0111110011100000011 |
3 | 220110210112020102001222 |
4 | 3232123022332130003 |
5 | 13143300120304011 |
6 | 313335133545255 |
7 | 24332035430024 |
oct | 3563312763403 |
9 | 813715212058 |
10 | 256006416131 |
11 | 99631a47624 |
12 | 4174804522b |
13 | 1b1ab59318b |
14 | c568410c4b |
15 | 69d52bcddb |
hex | 3b9b2be703 |
256006416131 has 4 divisors (see below), whose sum is σ = 257026362264. Its totient is φ = 254986470000.
The previous prime is 256006416103. The next prime is 256006416139. The reversal of 256006416131 is 131614600652.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 256006416131 - 230 = 254932674307 is a prime.
It is a super-2 number, since 2×2560064161312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 256006416091 and 256006416100.
It is not an unprimeable number, because it can be changed into a prime (256006416139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509972690 + ... + 509973191.
It is an arithmetic number, because the mean of its divisors is an integer number (64256590566).
Almost surely, 2256006416131 is an apocalyptic number.
256006416131 is a deficient number, since it is larger than the sum of its proper divisors (1019946133).
256006416131 is a wasteful number, since it uses less digits than its factorization.
256006416131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1019946132.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 256006416131 in words is "two hundred fifty-six billion, six million, four hundred sixteen thousand, one hundred thirty-one".
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