2560412137 has 4 divisors (see below), whose sum is σ = 2591260560. Its totient is φ = 2529563716.

The previous prime is 2560412093. The next prime is 2560412149. The reversal of 2560412137 is 7312140652.

2560412137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2560412137 - 2⁷ = 2560412009 is a prime.

It is a super-2 number, since 2×2560412137² = 13111420622593813538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2560412099 and 2560412108.

It is not an unprimeable number, because it can be changed into a prime (2560412537) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15424087 + ... + 15424252.

It is an arithmetic number, because the mean of its divisors is an integer number (647815140).

Almost surely, 2^2560412137 is an apocalyptic number.

It is an amenable number.

2560412137 is a deficient number, since it is larger than the sum of its proper divisors (30848423).

2560412137 is an equidigital number, since it uses as much as digits as its factorization.

2560412137 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30848422.

The product of its (nonzero) digits is 10080, while the sum is 31.

The square root of 2560412137 is about 50600.5151851244. The cubic root of 2560412137 is about 1368.0541642727.

Adding to 2560412137 its reverse (7312140652), we get a palindrome (9872552789).

The spelling of 2560412137 in words is "two billion, five hundred sixty million, four hundred twelve thousand, one hundred thirty-seven".