Base | Representation |
---|---|
bin | 1110111010000010011… |
… | …1100001100100000001 |
3 | 220111000220011111010101 |
4 | 3232200213201210001 |
5 | 13143442013123423 |
6 | 313352200202401 |
7 | 24334225156561 |
oct | 3564047414401 |
9 | 814026144111 |
10 | 256097786113 |
11 | 99679584204 |
12 | 41772769401 |
13 | 1b1c44a4860 |
14 | c5765d6da1 |
15 | 69dd31a7ad |
hex | 3ba09e1901 |
256097786113 has 4 divisors (see below), whose sum is σ = 275797615828. Its totient is φ = 236397956400.
The previous prime is 256097786083. The next prime is 256097786159. The reversal of 256097786113 is 311687790652.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 146021808384 + 110075977729 = 382128^2 + 331777^2 .
It is a cyclic number.
It is not a de Polignac number, because 256097786113 - 217 = 256097655041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (256097786173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9849914838 + ... + 9849914863.
It is an arithmetic number, because the mean of its divisors is an integer number (68949403957).
Almost surely, 2256097786113 is an apocalyptic number.
It is an amenable number.
256097786113 is a deficient number, since it is larger than the sum of its proper divisors (19699829715).
256097786113 is a wasteful number, since it uses less digits than its factorization.
256097786113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19699829714.
The product of its (nonzero) digits is 3810240, while the sum is 55.
The spelling of 256097786113 in words is "two hundred fifty-six billion, ninety-seven million, seven hundred eighty-six thousand, one hundred thirteen".
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