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2561016035 = 5512203207
BaseRepresentation
bin1001100010100110…
…0000000011100011
320121111000002112202
42120221200003203
520221110003120
61102043243415
7120315164024
oct23051400343
96544002482
102561016035
1110a4699286
125b581956b
1331a773a06
141a41b4c4b
15eec7e875
hex98a600e3

2561016035 has 4 divisors (see below), whose sum is σ = 3073219248. Its totient is φ = 2048812824.

The previous prime is 2561016011. The next prime is 2561016037. The reversal of 2561016035 is 5306101652.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2561016035 - 218 = 2560753891 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2561015989 and 2561016007.

It is not an unprimeable number, because it can be changed into a prime (2561016037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 256101599 + ... + 256101608.

It is an arithmetic number, because the mean of its divisors is an integer number (768304812).

Almost surely, 22561016035 is an apocalyptic number.

2561016035 is a deficient number, since it is larger than the sum of its proper divisors (512203213).

2561016035 is an equidigital number, since it uses as much as digits as its factorization.

2561016035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 512203212.

The product of its (nonzero) digits is 5400, while the sum is 29.

The square root of 2561016035 is about 50606.4821440890. The cubic root of 2561016035 is about 1368.1617120925.

Adding to 2561016035 its reverse (5306101652), we get a palindrome (7867117687).

The spelling of 2561016035 in words is "two billion, five hundred sixty-one million, sixteen thousand, thirty-five".

Divisors: 1 5 512203207 2561016035