Base | Representation |
---|---|
bin | 1110111010000111000… |
… | …0000100110010100001 |
3 | 220111002012221201211001 |
4 | 3232201300010302201 |
5 | 13144011400223034 |
6 | 313354115552001 |
7 | 24334545630550 |
oct | 3564160046241 |
9 | 814065851731 |
10 | 256116804769 |
11 | 99689294201 |
12 | 41778bbb601 |
13 | 1b1c84033b7 |
14 | c578d47d97 |
15 | 69ded25a14 |
hex | 3ba1c04ca1 |
256116804769 has 4 divisors (see below), whose sum is σ = 292704919744. Its totient is φ = 219528689796.
The previous prime is 256116804767. The next prime is 256116804829. The reversal of 256116804769 is 967408611652.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 256116804769 - 21 = 256116804767 is a prime.
It is a super-2 number, since 2×2561168047692 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (256116804767) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18294057477 + ... + 18294057490.
It is an arithmetic number, because the mean of its divisors is an integer number (73176229936).
Almost surely, 2256116804769 is an apocalyptic number.
It is an amenable number.
256116804769 is a deficient number, since it is larger than the sum of its proper divisors (36588114975).
256116804769 is an equidigital number, since it uses as much as digits as its factorization.
256116804769 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36588114974.
The product of its (nonzero) digits is 4354560, while the sum is 55.
The spelling of 256116804769 in words is "two hundred fifty-six billion, one hundred sixteen million, eight hundred four thousand, seven hundred sixty-nine".
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