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25613434206643 = 191134101749773
BaseRepresentation
bin1011101001011100101111…
…01001011011100110110011
310100200121202021021002120011
411310232113221123212303
511324122303124103033
6130250352122355351
75252336530350223
oct564562751334663
9110617667232504
1025613434206643
118185661961408
122a5807b35bb57
13113a44b3343aa
146479a8160083
152e63e6a45ccd
hex174b97a5b9b3

25613434206643 has 4 divisors (see below), whose sum is σ = 25747535956608. Its totient is φ = 25479332456680.

The previous prime is 25613434206631. The next prime is 25613434206667. The reversal of 25613434206643 is 34660243431652.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25613434206643 - 217 = 25613434075571 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25613435206643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67050874696 + ... + 67050875077.

It is an arithmetic number, because the mean of its divisors is an integer number (6436883989152).

Almost surely, 225613434206643 is an apocalyptic number.

25613434206643 is a deficient number, since it is larger than the sum of its proper divisors (134101749965).

25613434206643 is a wasteful number, since it uses less digits than its factorization.

25613434206643 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134101749964.

The product of its (nonzero) digits is 7464960, while the sum is 49.

The spelling of 25613434206643 in words is "twenty-five trillion, six hundred thirteen billion, four hundred thirty-four million, two hundred six thousand, six hundred forty-three".

Divisors: 1 191 134101749773 25613434206643