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2561425053441 = 32513401626897
BaseRepresentation
bin100101010001100000110…
…101001001011100000001
3100001212111010010120202220
4211101200311021130001
5313431244303202231
65240411420201253
7353025333502032
oct45214065113401
910055433116686
102561425053441
118a8326737061
12354508099229
131577064503c7
148bd8b91aa89
1546966506896
hex25460d49701

2561425053441 has 8 divisors (see below), whose sum is σ = 3428839913184. Its totient is φ = 1700813448000.

The previous prime is 2561425053419. The next prime is 2561425053443. The reversal of 2561425053441 is 1443505241652.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2561425053441 - 221 = 2561422956289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2561425053393 and 2561425053402.

It is not an unprimeable number, because it can be changed into a prime (2561425053443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1700812696 + ... + 1700814201.

It is an arithmetic number, because the mean of its divisors is an integer number (428604989148).

Almost surely, 22561425053441 is an apocalyptic number.

It is an amenable number.

2561425053441 is a deficient number, since it is larger than the sum of its proper divisors (867414859743).

2561425053441 is a wasteful number, since it uses less digits than its factorization.

2561425053441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3401627151.

The product of its (nonzero) digits is 576000, while the sum is 42.

The spelling of 2561425053441 in words is "two trillion, five hundred sixty-one billion, four hundred twenty-five million, fifty-three thousand, four hundred forty-one".

Divisors: 1 3 251 753 3401626897 10204880691 853808351147 2561425053441