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2562140133121 = 3118238392711
BaseRepresentation
bin100101010010001011011…
…100111101011100000001
3100001221022221200101200111
4211102023130331130001
5313434230333224441
65241010402551321
7353052135540322
oct45221334753401
910057287611614
102562140133121
118a8663345aa8
12354687668541
131577bb63c48a
148c01889c449
15469a91a7081
hex2548b73d701

2562140133121 has 4 divisors (see below), whose sum is σ = 2570378526144. Its totient is φ = 2553901740100.

The previous prime is 2562140133023. The next prime is 2562140133149. The reversal of 2562140133121 is 1213310412652.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2562140133121 - 215 = 2562140100353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2562140133221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4119196045 + ... + 4119196666.

It is an arithmetic number, because the mean of its divisors is an integer number (642594631536).

Almost surely, 22562140133121 is an apocalyptic number.

It is an amenable number.

2562140133121 is a deficient number, since it is larger than the sum of its proper divisors (8238393023).

2562140133121 is an equidigital number, since it uses as much as digits as its factorization.

2562140133121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8238393022.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 2562140133121 its reverse (1213310412652), we get a palindrome (3775450545773).

The spelling of 2562140133121 in words is "two trillion, five hundred sixty-two billion, one hundred forty million, one hundred thirty-three thousand, one hundred twenty-one".

Divisors: 1 311 8238392711 2562140133121