Base | Representation |
---|---|
bin | 111010011100101011000000… |
… | …000100100000101000100011 |
3 | 1020201011102002100200010012120 |
4 | 322130223000010200220203 |
5 | 232143110231324321230 |
6 | 2310414210143155323 |
7 | 105100520316320532 |
oct | 7234530004405043 |
9 | 1221142070603176 |
10 | 257057015073315 |
11 | 749a72a4601186 |
12 | 249b74562a5b43 |
13 | b0584ac52cc42 |
14 | 47698a9716319 |
15 | 1eab999a88310 |
hex | e9cac0120a23 |
257057015073315 has 8 divisors (see below), whose sum is σ = 411291224117328. Its totient is φ = 137097074705760.
The previous prime is 257057015073289. The next prime is 257057015073347. The reversal of 257057015073315 is 513370510750752.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 257057015073315 - 26 = 257057015073251 is a prime.
It is a super-2 number, since 2×2570570150733152 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8568567169096 + ... + 8568567169125.
It is an arithmetic number, because the mean of its divisors is an integer number (51411403014666).
Almost surely, 2257057015073315 is an apocalyptic number.
257057015073315 is a deficient number, since it is larger than the sum of its proper divisors (154234209044013).
257057015073315 is a wasteful number, since it uses less digits than its factorization.
257057015073315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17137134338229.
The product of its (nonzero) digits is 3858750, while the sum is 51.
The spelling of 257057015073315 in words is "two hundred fifty-seven trillion, fifty-seven billion, fifteen million, seventy-three thousand, three hundred fifteen".
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