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257913605057 = 530034866019
BaseRepresentation
bin1111000000110011011…
…0010100101111000001
3220122201102221122102212
43300030312110233001
513211201340330212
6314252303351505
724430224320423
oct3601466245701
9818642848385
10257913605057
119a420562919
1241b9a8b2595
131b423742c34
14c6a982a813
156a9794ae22
hex3c0cd94bc1

257913605057 has 4 divisors (see below), whose sum is σ = 257918524080. Its totient is φ = 257908686036.

The previous prime is 257913605039. The next prime is 257913605071. The reversal of 257913605057 is 750506319752.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 257913605057 - 28 = 257913604801 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 257913604996 and 257913605014.

It is not an unprimeable number, because it can be changed into a prime (257913605857) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2380007 + ... + 2486012.

It is an arithmetic number, because the mean of its divisors is an integer number (64479631020).

Almost surely, 2257913605057 is an apocalyptic number.

It is an amenable number.

257913605057 is a deficient number, since it is larger than the sum of its proper divisors (4919023).

257913605057 is an equidigital number, since it uses as much as digits as its factorization.

257913605057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4919022.

The product of its (nonzero) digits is 1984500, while the sum is 50.

The spelling of 257913605057 in words is "two hundred fifty-seven billion, nine hundred thirteen million, six hundred five thousand, fifty-seven".

Divisors: 1 53003 4866019 257913605057