Base | Representation |
---|---|
bin | 100101100010111100010… |
… | …010011111011010000001 |
3 | 100010122210100100220201200 |
4 | 211202330102133122001 |
5 | 314233111132411231 |
6 | 5253144420251413 |
7 | 354260154354324 |
oct | 45427422373201 |
9 | 10118710326650 |
10 | 2580139341441 |
11 | 90525a437682 |
12 | 35806b540b69 |
13 | 1593c96535bc |
14 | 8cc451607bb |
15 | 471ae455be6 |
hex | 258bc49f681 |
2580139341441 has 12 divisors (see below), whose sum is σ = 3888905674368. Its totient is φ = 1645306246584.
The previous prime is 2580139341419. The next prime is 2580139341449. The reversal of 2580139341441 is 1441439310852.
2580139341441 is a `hidden beast` number, since 2 + 5 + 80 + 1 + 3 + 93 + 41 + 441 = 666.
It is not a de Polignac number, because 2580139341441 - 213 = 2580139333249 is a prime.
It is a hoax number, since the sum of its digits (45) coincides with the sum of the digits of its distinct prime factors.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (2580139341449) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6232220425 + ... + 6232220838.
It is an arithmetic number, because the mean of its divisors is an integer number (324075472864).
Almost surely, 22580139341441 is an apocalyptic number.
It is an amenable number.
2580139341441 is a deficient number, since it is larger than the sum of its proper divisors (1308766332927).
2580139341441 is a wasteful number, since it uses less digits than its factorization.
2580139341441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12464441292 (or 12464441289 counting only the distinct ones).
The product of its (nonzero) digits is 414720, while the sum is 45.
The spelling of 2580139341441 in words is "two trillion, five hundred eighty billion, one hundred thirty-nine million, three hundred forty-one thousand, four hundred forty-one".
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