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25990419193 = 137189711089
BaseRepresentation
bin11000001101001001…
…100101001011111001
32111002022120002112021
4120031021211023321
5411212021403233
615535000514441
71610031626614
oct301511451371
974068502467
1025990419193
1110027a06692
12505417ba21
1325b279a88b
141387b1d17b
15a21b0ee2d
hex60d2652f9

25990419193 has 4 divisors (see below), whose sum is σ = 26180130420. Its totient is φ = 25800707968.

The previous prime is 25990419149. The next prime is 25990419197. The reversal of 25990419193 is 39191409952.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11323513744 + 14666905449 = 106412^2 + 121107^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25990419193 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 25990419193.

It is not an unprimeable number, because it can be changed into a prime (25990419197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94855408 + ... + 94855681.

It is an arithmetic number, because the mean of its divisors is an integer number (6545032605).

Almost surely, 225990419193 is an apocalyptic number.

It is an amenable number.

25990419193 is a deficient number, since it is larger than the sum of its proper divisors (189711227).

25990419193 is a wasteful number, since it uses less digits than its factorization.

25990419193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 189711226.

The product of its (nonzero) digits is 787320, while the sum is 52.

The spelling of 25990419193 in words is "twenty-five billion, nine hundred ninety million, four hundred nineteen thousand, one hundred ninety-three".

Divisors: 1 137 189711089 25990419193