2632134631441 has 4 divisors (see below), whose sum is σ = 3008153864512. Its totient is φ = 2256115398372.

The previous prime is 2632134631439. The next prime is 2632134631447. The reversal of 2632134631441 is 1441364312362.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2632134631441 - 2¹ = 2632134631439 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2632134631394 and 2632134631403.

It is not an unprimeable number, because it can be changed into a prime (2632134631447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188009616525 + ... + 188009616538.

It is an arithmetic number, because the mean of its divisors is an integer number (752038466128).

Almost surely, 2^{2632134631441} is an apocalyptic number.

It is an amenable number.

2632134631441 is a deficient number, since it is larger than the sum of its proper divisors (376019233071).

2632134631441 is an equidigital number, since it uses as much as digits as its factorization.

2632134631441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 376019233070.

The product of its digits is 248832, while the sum is 40.

The spelling of 2632134631441 in words is "two trillion, six hundred thirty-two billion, one hundred thirty-four million, six hundred thirty-one thousand, four hundred forty-one".