Base | Representation |
---|---|
bin | 1011111110100110101101… |
… | …01111000101010000100011 |
3 | 10110021010000201202101220012 |
4 | 11333103112233011100203 |
5 | 11423030010041004403 |
6 | 132004330334035135 |
7 | 5356012142616122 |
oct | 577232657052043 |
9 | 113233021671805 |
10 | 26340342125603 |
11 | 8435970490860 |
12 | 2b54b27348aab |
13 | 1190b6438196c |
14 | 670c44d77ab9 |
15 | 30a28d044ed8 |
hex | 17f4d6bc5423 |
26340342125603 has 8 divisors (see below), whose sum is σ = 28746008994816. Its totient is φ = 23936523641800.
The previous prime is 26340342125599. The next prime is 26340342125621. The reversal of 26340342125603 is 30652124304362.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 26340342125603 - 22 = 26340342125599 is a prime.
It is a super-2 number, since 2×263403421256032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (26340342125623) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 462066551 + ... + 462123552.
It is an arithmetic number, because the mean of its divisors is an integer number (3593251124352).
Almost surely, 226340342125603 is an apocalyptic number.
26340342125603 is a deficient number, since it is larger than the sum of its proper divisors (2405666869213).
26340342125603 is a wasteful number, since it uses less digits than its factorization.
26340342125603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 924192705.
The product of its (nonzero) digits is 622080, while the sum is 41.
Adding to 26340342125603 its reverse (30652124304362), we get a palindrome (56992466429965).
The spelling of 26340342125603 in words is "twenty-six trillion, three hundred forty billion, three hundred forty-two million, one hundred twenty-five thousand, six hundred three".
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