Base | Representation |
---|---|
bin | 11000100010010000… |
… | …110111010110010011 |
3 | 2112000000002220000122 |
4 | 120202100313112103 |
5 | 412423212301011 |
6 | 20034053140455 |
7 | 1621562555102 |
oct | 304220672623 |
9 | 75000086018 |
10 | 26344650131 |
11 | 10199960628 |
12 | 513292a72b |
13 | 263aca5797 |
14 | 13bcbac039 |
15 | a42c823db |
hex | 622437593 |
26344650131 has 4 divisors (see below), whose sum is σ = 26348002512. Its totient is φ = 26341297752.
The previous prime is 26344650103. The next prime is 26344650139. The reversal of 26344650131 is 13105644362.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 26344650131 - 26 = 26344650067 is a prime.
It is a super-2 number, since 2×263446501312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 26344650091 and 26344650100.
It is not an unprimeable number, because it can be changed into a prime (26344650139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1664375 + ... + 1680128.
It is an arithmetic number, because the mean of its divisors is an integer number (6587000628).
Almost surely, 226344650131 is an apocalyptic number.
26344650131 is a deficient number, since it is larger than the sum of its proper divisors (3352381).
26344650131 is an equidigital number, since it uses as much as digits as its factorization.
26344650131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3352380.
The product of its (nonzero) digits is 51840, while the sum is 35.
The spelling of 26344650131 in words is "twenty-six billion, three hundred forty-four million, six hundred fifty thousand, one hundred thirty-one".
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