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2634650130243 = 3878216710081
BaseRepresentation
bin100110010101101101011…
…000101001011101000011
3100022212111022000220022110
4212111231120221131003
5321131230413131433
65334201435510403
7361230041413665
oct46255530513503
910285438026273
102634650130243
1192639234a05a
12366742bb8403
131615a5aa6711
14917369a8535
15487eed1a963
hex2656d629743

2634650130243 has 4 divisors (see below), whose sum is σ = 3512866840328. Its totient is φ = 1756433420160.

The previous prime is 2634650130173. The next prime is 2634650130257. The reversal of 2634650130243 is 3420310564362.

2634650130243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2634650130243 - 214 = 2634650113859 is a prime.

It is a super-3 number, since 3×26346501302433 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2634650130263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 439108355038 + ... + 439108355043.

It is an arithmetic number, because the mean of its divisors is an integer number (878216710082).

Almost surely, 22634650130243 is an apocalyptic number.

2634650130243 is a deficient number, since it is larger than the sum of its proper divisors (878216710085).

2634650130243 is an equidigital number, since it uses as much as digits as its factorization.

2634650130243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 878216710084.

The product of its (nonzero) digits is 311040, while the sum is 39.

The spelling of 2634650130243 in words is "two trillion, six hundred thirty-four billion, six hundred fifty million, one hundred thirty thousand, two hundred forty-three".

Divisors: 1 3 878216710081 2634650130243