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264112090433 = 6728031140629
BaseRepresentation
bin1111010111111001001…
…1101010110101000001
3221020201102111022212022
43311332103222311001
513311400143343213
6321155330411225
725036641504362
oct3657623526501
9836642438768
10264112090433
11a2011431704
124322a730b15
131bba0985769
14cad6b45b69
156d0bbde308
hex3d7e4ead41

264112090433 has 8 divisors (see below), whose sum is σ = 268065530880. Its totient is φ = 260158987440.

The previous prime is 264112090379. The next prime is 264112090471. The reversal of 264112090433 is 334090211462.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 264112090433 - 214 = 264112074049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 264112090393 and 264112090402.

It is not an unprimeable number, because it can be changed into a prime (264112090733) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1807763 + ... + 1948391.

It is an arithmetic number, because the mean of its divisors is an integer number (33508191360).

Almost surely, 2264112090433 is an apocalyptic number.

It is an amenable number.

264112090433 is a deficient number, since it is larger than the sum of its proper divisors (3953440447).

264112090433 is a wasteful number, since it uses less digits than its factorization.

264112090433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 168727.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 264112090433 in words is "two hundred sixty-four billion, one hundred twelve million, ninety thousand, four hundred thirty-three".

Divisors: 1 67 28031 140629 1878077 9422143 3941971499 264112090433