Base | Representation |
---|---|
bin | 11000100111000101… |
… | …011001011111000011 |
3 | 2112012122022000202201 |
4 | 120213011121133003 |
5 | 413104413432212 |
6 | 20050102454031 |
7 | 1623564205261 |
oct | 304705313703 |
9 | 75178260681 |
10 | 26425530307 |
11 | 10230583050 |
12 | 5155a34317 |
13 | 2651983687 |
14 | 13c9823431 |
15 | a49e0bb57 |
hex | 6271597c3 |
26425530307 has 8 divisors (see below), whose sum is σ = 29821915440. Its totient is φ = 23194822560.
The previous prime is 26425530281. The next prime is 26425530379. The reversal of 26425530307 is 70303552462.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 26425530307 - 27 = 26425530179 is a prime.
It is a super-3 number, since 3×264255303073 (a number of 32 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (26425530007) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41419008 + ... + 41419645.
It is an arithmetic number, because the mean of its divisors is an integer number (3727739430).
Almost surely, 226425530307 is an apocalyptic number.
26425530307 is a deficient number, since it is larger than the sum of its proper divisors (3396385133).
26425530307 is a wasteful number, since it uses less digits than its factorization.
26425530307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82838693.
The product of its (nonzero) digits is 151200, while the sum is 37.
The spelling of 26425530307 in words is "twenty-six billion, four hundred twenty-five million, five hundred thirty thousand, three hundred seven".
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