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265720664113 = 1901139779413
BaseRepresentation
bin1111011101111000101…
…1111001000000110001
3221101212112022100010021
43313132023321000301
513323143442222423
6322023112003441
725124543243512
oct3673613710061
9841775270107
10265720664113
11a2767429943
12435b9390581
131c099000ac8
14cc0a62ca09
156da303395d
hex3dde2f9031

265720664113 has 4 divisors (see below), whose sum is σ = 265860445428. Its totient is φ = 265580882800.

The previous prime is 265720664063. The next prime is 265720664207. The reversal of 265720664113 is 311466027562.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 52616560689 + 213104103424 = 229383^2 + 461632^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-265720664113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 265720664113.

It is not an unprimeable number, because it can be changed into a prime (265726664113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69887806 + ... + 69891607.

It is an arithmetic number, because the mean of its divisors is an integer number (66465111357).

Almost surely, 2265720664113 is an apocalyptic number.

It is an amenable number.

265720664113 is a deficient number, since it is larger than the sum of its proper divisors (139781315).

265720664113 is a wasteful number, since it uses less digits than its factorization.

265720664113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139781314.

The product of its (nonzero) digits is 362880, while the sum is 43.

The spelling of 265720664113 in words is "two hundred sixty-five billion, seven hundred twenty million, six hundred sixty-four thousand, one hundred thirteen".

Divisors: 1 1901 139779413 265720664113