Base | Representation |
---|---|
bin | 11000110010110110… |
… | …111001000101000011 |
3 | 2112201101222021112111 |
4 | 120302312321011003 |
5 | 414011000213042 |
6 | 20121440240151 |
7 | 1631513140444 |
oct | 306266710503 |
9 | 75641867474 |
10 | 26623054147 |
11 | 10322024698 |
12 | 51b0010057 |
13 | 26838818a1 |
14 | 1407b5d2cb |
15 | a5c427517 |
hex | 632db9143 |
26623054147 has 4 divisors (see below), whose sum is σ = 26627173560. Its totient is φ = 26618934736.
The previous prime is 26623054091. The next prime is 26623054177. The reversal of 26623054147 is 74145032662.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 26623054147 - 27 = 26623054019 is a prime.
It is a super-3 number, since 3×266230541473 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (26623054177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2049997 + ... + 2062942.
It is an arithmetic number, because the mean of its divisors is an integer number (6656793390).
Almost surely, 226623054147 is an apocalyptic number.
26623054147 is a deficient number, since it is larger than the sum of its proper divisors (4119413).
26623054147 is an equidigital number, since it uses as much as digits as its factorization.
26623054147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4119412.
The product of its (nonzero) digits is 241920, while the sum is 40.
The spelling of 26623054147 in words is "twenty-six billion, six hundred twenty-three million, fifty-four thousand, one hundred forty-seven".
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