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26734029433 = 139192331147
BaseRepresentation
bin11000111001011110…
…001110101001111001
32120000010210102000021
4120321132032221321
5414222402420213
620140443010441
71634331333526
oct307136165171
976003712007
1026734029433
1110379732001
125221209a21
1326a0868b37
1414187aa14d
15a67048d8d
hex63978ea79

26734029433 has 4 divisors (see below), whose sum is σ = 26926360720. Its totient is φ = 26541698148.

The previous prime is 26734029419. The next prime is 26734029451. The reversal of 26734029433 is 33492043762.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 26734029433 - 29 = 26734028921 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 26734029433.

It is not an unprimeable number, because it can be changed into a prime (26734026433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96165435 + ... + 96165712.

It is an arithmetic number, because the mean of its divisors is an integer number (6731590180).

Almost surely, 226734029433 is an apocalyptic number.

It is an amenable number.

26734029433 is a deficient number, since it is larger than the sum of its proper divisors (192331287).

26734029433 is a wasteful number, since it uses less digits than its factorization.

26734029433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192331286.

The product of its (nonzero) digits is 653184, while the sum is 43.

The spelling of 26734029433 in words is "twenty-six billion, seven hundred thirty-four million, twenty-nine thousand, four hundred thirty-three".

Divisors: 1 139 192331147 26734029433