Base | Representation |
---|---|
bin | 1111100111010011101… |
… | …1111100001100000001 |
3 | 221122101210101220112101 |
4 | 3321310323330030001 |
5 | 13343333424424213 |
6 | 323122101030401 |
7 | 25244324016316 |
oct | 3716473741401 |
9 | 848353356471 |
10 | 268249842433 |
11 | a3845051a61 |
12 | 43ba43b5401 |
13 | 1c3acca8221 |
14 | cdaa4b6d0d |
15 | 6ea00c4bdd |
hex | 3e74efc301 |
268249842433 has 4 divisors (see below), whose sum is σ = 268252830720. Its totient is φ = 268246854148.
The previous prime is 268249842401. The next prime is 268249842481. The reversal of 268249842433 is 334248942862.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 268249842433 - 25 = 268249842401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (268249842233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1355185 + ... + 1540462.
It is an arithmetic number, because the mean of its divisors is an integer number (67063207680).
Almost surely, 2268249842433 is an apocalyptic number.
It is an amenable number.
268249842433 is a deficient number, since it is larger than the sum of its proper divisors (2988287).
268249842433 is an equidigital number, since it uses as much as digits as its factorization.
268249842433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2988286.
The product of its digits is 15925248, while the sum is 55.
The spelling of 268249842433 in words is "two hundred sixty-eight billion, two hundred forty-nine million, eight hundred forty-two thousand, four hundred thirty-three".
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