Base | Representation |
---|---|
bin | 110011101100… |
… | …0101110100001 |
3 | 1212222221002222 |
4 | 1213120232201 |
5 | 23414231423 |
6 | 2404520425 |
7 | 446235623 |
oct | 147305641 |
9 | 55887088 |
10 | 27102113 |
11 | 14331245 |
12 | 90b0115 |
13 | 57cbc6c |
14 | 3856c13 |
15 | 25a53c8 |
hex | 19d8ba1 |
27102113 has 4 divisors (see below), whose sum is σ = 28528560. Its totient is φ = 25675668.
The previous prime is 27102079. The next prime is 27102149. The reversal of 27102113 is 31120172.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 27102113 - 28 = 27101857 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 27102091 and 27102100.
It is not an unprimeable number, because it can be changed into a prime (27102613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 713195 + ... + 713232.
It is an arithmetic number, because the mean of its divisors is an integer number (7132140).
Almost surely, 227102113 is an apocalyptic number.
It is an amenable number.
27102113 is a deficient number, since it is larger than the sum of its proper divisors (1426447).
27102113 is a wasteful number, since it uses less digits than its factorization.
27102113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1426446.
The product of its (nonzero) digits is 84, while the sum is 17.
The square root of 27102113 is about 5205.9689780098. The cubic root of 27102113 is about 300.3777205207.
Adding to 27102113 its reverse (31120172), we get a palindrome (58222285).
The spelling of 27102113 in words is "twenty-seven million, one hundred two thousand, one hundred thirteen".
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