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2743325506657 = 20123136327859
BaseRepresentation
bin100111111010111010111…
…100010011110001100001
3100201021000001221000201201
4213322322330103301201
5324421312312203112
65500133310201201
7402125110030051
oct47727274236141
910637001830651
102743325506657
1196848a80392a
123838121b3201
1316b904a26888
1496ac5c9b561
154b5609ac257
hex27ebaf13c61

2743325506657 has 4 divisors (see below), whose sum is σ = 2743461854640. Its totient is φ = 2743189158676.

The previous prime is 2743325506631. The next prime is 2743325506703. The reversal of 2743325506657 is 7566055233472.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2743325506657 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2743325506598 and 2743325506607.

It is not an unprimeable number, because it can be changed into a prime (2743325006657) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68143807 + ... + 68184052.

It is an arithmetic number, because the mean of its divisors is an integer number (685865463660).

Almost surely, 22743325506657 is an apocalyptic number.

It is an amenable number.

2743325506657 is a deficient number, since it is larger than the sum of its proper divisors (136347983).

2743325506657 is a wasteful number, since it uses less digits than its factorization.

2743325506657 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 136347982.

The product of its (nonzero) digits is 31752000, while the sum is 55.

The spelling of 2743325506657 in words is "two trillion, seven hundred forty-three billion, three hundred twenty-five million, five hundred six thousand, six hundred fifty-seven".

Divisors: 1 20123 136327859 2743325506657